python3.8中li=[]li[0]=1出错

  • Z时代
  • 2024-01-10
  • 分类：综合

python

# coding:utf-8
# 下面是归并排序 中 出现的一些语法的错误
def MergeSort(array: [], startIndex: int, endIndex: int):
    if startIndex >= endIndex:
        return
    # mid = (startIndex + endIndex)//2 +1
    mid = startIndex + (endIndex - startIndex) // 2 #python // 才能表示整除 使用 / 会出现float类型
    MergeSort(array, startIndex, mid)
    MergeSort(array, mid + 1, endIndex)
    Merge(array, startIndex, mid, endIndex)


def Merge(array: [], startIndex: int, mid: int, endIndex: int):
    tempLi = []
    # mid = startIndex + (endIndex - startIndex) / 2
    # mid = (startIndex + endIndex) / 2
    p = 0
    p1 = startIndex
    p2 = mid + 1
    while p1 <= mid and p2 <= endIndex:
        if array[p1] <= array[p2]:
            tempLi.append(array[p1])
            p += 1
            p1 += 1

        else:
            tempLi.append(array[p2])
            p += 1
            p2 += 1

    while p1 <= mid:
        tempLi.append(array[p1])
        # tempLi[p] = array[p1]
        p += 1
        p1 += 1
    while p2 <= endIndex:
        tempLi.append(array[p2])
　　　　　#当tempLi为空的时候 ，不能通过下标来索引
        # tempLi[p] = array[p2]
        p += 1
        p2 += 1
    for i in range(0, tempLi.__len__()):
        array[startIndex + i] = tempLi[i]


if __name__ == "__main__":
    from random import randint

    array = [randint(1, 10) for i in range(10)]
    print(f"原来的：{array}")
    MergeSort(array, 0, array.__len__() - 1)
    print(f"现在的：{array}")

以上是 python3.8中li=[]li[0]=1出错 的全部内容， 来源链接： utcz.com/z/530247.html

回到顶部